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Mathematics
Mathematics
Problem
Given
x
=
a
t
1
+
t
2
x=\dfrac{at}{1+t^2}
x
=
1
+
t
2
a
t
and
y
=
a
(
1
−
t
2
)
1
+
t
2
y=\dfrac{a(1-t^2)}{1+t^2}
y
=
1
+
t
2
a
(
1
−
t
2
)
, which of the following equals
d
y
d
x
\dfrac{dy}{dx}
d
x
d
y
? a)
4
t
1
−
t
2
\dfrac{4t}{1-t^{2}}
1
−
t
2
4
t
b)
−
4
t
1
+
t
2
\dfrac{-4t}{1+t^{2}}
1
+
t
2
−
4
t
c)
−
4
t
1
−
t
2
\dfrac{-4t}{1-t^{2}}
1
−
t
2
−
4
t
d)
−
2
t
1
−
t
2
\dfrac{-2t}{1-t^{2}}
1
−
t
2
−
2
t
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