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Physics
Physics
Problem
For a rotating disk, the torque as a function of angular position is given by
τ
(
θ
)
=
4.5
sin
θ
N
⋅
m
\tau(\theta) = 4.5\,\sin \theta\,\text{N}\cdot\text{m}
τ
(
θ
)
=
4.5
sin
θ
N
⋅
m
for
0
≤
θ
≤
π
2
rad
0 \leq \theta \leq \frac{\pi}{2}\,\text{rad}
0
≤
θ
≤
2
π
rad
. Calculate the rotational work done on the disk as it turns from
θ
=
0
\theta = 0
θ
=
0
to
θ
=
π
2
rad
\theta = \frac{\pi}{2}\,\text{rad}
θ
=
2
π
rad
.
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