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Mathematics
Mathematics
Problem
d
d
x
[
2
π
sin
x
0
]
=
\frac{d}{dx} \left[ \frac{2}{\pi} \sin x^0 \right] =
d
x
d
[
π
2
sin
x
0
]
=
(a)
π
180
cos
x
0
\frac{\pi}{180} \cos x^0
180
π
cos
x
0
(b)
1
90
cos
x
0
\frac{1}{90} \cos x^0
90
1
cos
x
0
(c)
π
90
cos
x
0
\frac{\pi}{90} \cos x^0
90
π
cos
x
0
(d)
2
90
cos
x
0
\frac{2}{90} \cos x^0
90
2
cos
x
0
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