Mathematics

Mathematics

Problem

Prove that 1−tan⁡θ1+tan⁡θ=cos⁡θ−sin⁡θcos⁡θ+sin⁡θ\dfrac{1-\tan\theta}{1+\tan\theta}=\dfrac{\cos\theta-\sin\theta}{\cos\theta+\sin\theta}, given that cos⁡θ≠0\cos\theta\neq0 and cos⁡θ+sin⁡θ≠0\cos\theta+\sin\theta\neq0.

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