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Chemistry
Chemistry
Problem
Calculate the cell potential for a cell in which
[
Mn
2
+
]
=
0.005
M
[
Mn
3
+
]
=
0.1
M at
25
∘
C
.
[\text{Mn}^{2+}] = 0.005 \text{ M} \quad [\text{Mn}^{3+}] = 0.1 \text{ M} \text{ at } 25^\circ \text{C}.
[
Mn
2
+
]
=
0.005
M
[
Mn
3
+
]
=
0.1
M
at
2
5
∘
C
.
(Given: Standard reduction potential
Mn
3
+
/
Mn
2
+
\text{Mn}^{3+} / \text{Mn}^{2+}
Mn
3
+
/
Mn
2
+
is 1.57 V).
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