Physics

Problem

A proton of charge

1.6 \times 10^{-19}

C approaches the nucleus of a nitrogen atom head-on, with an initial kinetic energy of

1.6 \times 10^{-14}

J. The charge on the nitrogen nucleus is

1.12 \times 10^{-18}

k = 9 \times 10^9 \text{ Nm}^2\text{C}^{-2}

. Calculate the distance of closest approach for the proton and the nitrogen nucleus. Assume that the nitrogen nucleus does not move.