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Mathematics
Mathematics
Problem
Let
g
(
x
)
=
f
(
x
)
sin
x
g(x)=f(x)\sin x
g
(
x
)
=
f
(
x
)
sin
x
, where
f
(
x
)
f(x)
f
(
x
)
is a twice differentiable function on
(
−
∞
,
∞
)
(-\infty,\infty)
(
−
∞
,
∞
)
such that
f
′
(
−
π
)
=
1
f'(-\pi)=1
f
′
(
−
π
)
=
1
. The value of
∣
g
′
′
(
−
π
)
∣
|g''(-\pi)|
∣
g
′′
(
−
π
)
∣
equals.....
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