Lebl-Basic-Analysis-I · Problem 4.2.14

The Derivative

Mathematics · differentiability-extension

Problem

Suppose f:(0,1)→Rf : (0,1) \to \mathbb{R} is differentiable and f′f' is bounded. a) Show that there exists a continuous function g:[0,1)→Rg : [0,1) \to \mathbb{R} such that f(x)=g(x)f(x) = g(x) for all x≠0x \neq 0. Hint: Proposition 3.4.6 and Exercise 4.2.3. b) Find an example where the gg is not differentiable at x=0x = 0. Hint: Consider something based on sin⁡(ln⁡x)\sin(\ln x), and assume you know basic properties of sin⁡\sin and ln⁡\ln from calculus. c) Instead of assuming that f′f' is bounded, assume that lim⁡x→0f′(x)=L\lim_{x \to 0} f'(x) = L. Prove that not only does gg exist but it is differentiable at 00 and g′(0)=Lg'(0) = L.

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