When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is ____ Å. (Round off to the Nearest Integer).
[Use: 3=1.73, h=6.63×10−34 Js, me=9.1×10−31 kg; c=3.0×108 ms−1; 1 eV =1.6×10−19 J]