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Mathematics
Mathematics
Problem
The common tangent to the circles
x
2
+
y
2
=
4
x^2 + y^2 = 4
x
2
+
y
2
=
4
and
x
2
+
y
2
+
6
x
+
8
y
−
24
=
0
x^2 + y^2 + 6x + 8y - 24 = 0
x
2
+
y
2
+
6
x
+
8
y
−
24
=
0
also passes through point (1)
(
−
4
,
6
)
(-4, 6)
(
−
4
,
6
)
(2)
(
6
,
−
2
)
(6, -2)
(
6
,
−
2
)
(3)
(
−
6
,
4
)
(-6, 4)
(
−
6
,
4
)
(4)
(
4
,
−
2
)
(4, -2)
(
4
,
−
2
)
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