Mathematics

Problem

Normal form of line

x + \sqrt{3}y - 4 = 0

is :- (1)

x \cos\pi/3 - y \sin\pi/3 = 2

(3)

x \cos\pi/3 + y \sin\pi/3 = 2

(2)

x \cos\pi/6 - y \sin\pi/6 = 2

(4)

x \cos\pi/6 + y \sin\pi/6 = 2