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Mathematics
Problem
Prove the following (Exercises 32 to 37) 37.
∫
0
1
sin
−
1
x
d
x
=
π
2
−
1
\int_{0}^{1} \sin ^{-1} x d x=\frac{\pi}{2}-1
∫
0
1
sin
−
1
x
d
x
=
2
π
−
1
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