Chlorine’s molecule · Estonian PhO 2012 #6

Physics · mechanics

Problem

Chlorine’s molecule, which is moving with a velocity v=\SI600m/sv = \SI{600}{m/s}, absorbs a photon with a wavelength λ=\SI350nm\lambda = \SI{350}{nm} and is divided into two atoms. The first atom’s velocity is measured to be u=\SI1600m/s u = \SI{1600}{m/s}, which perpendicular to the molecule’s initial velocity. Find the chlorine molecule’s binding energy if all the particles were at a state with minimal inner energy. Planck constant is $h = \SI{6,6e-34}{J.s},speedoflightis, speed of light is c = \SI{3,0e8}{m/s},chlorine’satomicnumberis35andAvogadroconstantis, chlorine’s atomic number is 35 and Avogadro constant is N_A = \SI{6,0e23}{\text{mol}^{-1}}.Photon’senergyisdefinedas. Photon’s energy is defined as E = \frac{h c}{\lambda}$. It is presumed that a photon’s momentum is negligible compared to chlorine’s momentum.

Browse the problem library