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Mathematics
Mathematics
Problem
Prove that the radii of the circles
x
2
+
y
2
=
1
,
x
2
+
y
2
−
2
x
−
6
y
=
6
and
x^2 + y^2 = 1, x^2 + y^2 - 2x - 6y = 6 \quad \text{and}
x
2
+
y
2
=
1
,
x
2
+
y
2
−
2
x
−
6
y
=
6
and
x
2
+
y
2
−
4
x
−
12
y
=
9
are in AP.
x^2 + y^2 - 4x - 12y = 9 \text{ are in AP.}
x
2
+
y
2
−
4
x
−
12
y
=
9
are in AP.
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