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Physics
Physics
Problem
A solid ball of radius
R
R
R
has a charge density
ρ
\rho
ρ
given by
ρ
=
ρ
0
(
1
−
r
R
)
\rho = \rho_0 \left( 1 - \frac{r}{R} \right)
ρ
=
ρ
0
(
1
−
R
r
)
for
0
≤
r
≤
R
0 \le r \le R
0
≤
r
≤
R
. The electric field outside the ball is: a.
ρ
0
R
3
ϵ
0
r
2
\frac{\rho_0 R^3}{\epsilon_0 r^2}
ϵ
0
r
2
ρ
0
R
3
b.
4
ρ
0
R
3
3
ϵ
0
r
2
\frac{4\rho_0 R^3}{3\epsilon_0 r^2}
3
ϵ
0
r
2
4
ρ
0
R
3
c.
3
ρ
0
R
3
4
ϵ
0
r
2
\frac{3\rho_0 R^3}{4\epsilon_0 r^2}
4
ϵ
0
r
2
3
ρ
0
R
3
d.
ρ
0
R
3
12
ϵ
0
r
2
\frac{\rho_0 R^3}{12\epsilon_0 r^2}
12
ϵ
0
r
2
ρ
0
R
3
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