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Mathematics
Mathematics
Problem
Show that
sin
(
90
∘
−
θ
)
cos
(
90
∘
−
θ
)
+
cos
(
90
∘
−
θ
)
sin
(
90
∘
−
θ
)
=
cot
θ
+
tan
θ
.
\frac{\sin(90^{\circ}-\theta)}{\cos(90^{\circ}-\theta)}+\frac{\cos(90^{\circ}-\theta)}{\sin(90^{\circ}-\theta)}=\cot\theta+\tan\theta.
cos
(
9
0
∘
−
θ
)
sin
(
9
0
∘
−
θ
)
+
sin
(
9
0
∘
−
θ
)
cos
(
9
0
∘
−
θ
)
=
cot
θ
+
tan
θ
.
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