Chemistry

Chemistry

Problem

The rate of disappearance of AA at two temperatures is given by : A⇌BA \rightleftharpoons B I. −d[A]dt=2×10−2[A]−4×10−3[B]-\frac{d[A]}{dt} = 2 \times 10^{-2} [A] - 4 \times 10^{-3} [B] at 300 K300 \text{ K} II. −d[A]dt=4×10−2[A]−16×10−4[B]-\frac{d[A]}{dt} = 4 \times 10^{-2} [A] - 16 \times 10^{-4} [B] at 400 K400 \text{ K} The heat of reaction for the change is : a. 3.863 kcal3.863 \text{ kcal} b. 6.93 kcal6.93 \text{ kcal} c. 1.68 kcal1.68 \text{ kcal} d. 1.68×102 kcal1.68 \times 10^2 \text{ kcal}

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