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Mathematics
Mathematics
Problem
A function is defined by
h
(
x
)
=
{
x
2
−
1
x
−
1
,
x
≠
1
3
,
x
=
1
h(x)=\begin{cases}\dfrac{x^{2}-1}{x-1}, & x\ne 1\\3, & x=1\end{cases}
h
(
x
)
=
⎩
⎨
⎧
x
−
1
x
2
−
1
,
3
,
x
=
1
x
=
1
Explain why
h
h
h
is not continuous at
x
=
1
x=1
x
=
1
.
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