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Mathematics
Mathematics
Problem
By completing the square, show that the vertex of the parabola
y
=
a
x
2
+
b
x
+
c
y = ax^2 + bx + c
y
=
a
x
2
+
b
x
+
c
, where
a
≠
0
,
has coordinates
(
−
b
2
a
,
c
−
b
2
4
a
)
.
a \neq 0, \text{ has coordinates } \left( \frac{-b}{2a}, c - \frac{b^2}{4a} \right).
a
=
0
,
has coordinates
(
2
a
−
b
,
c
−
4
a
b
2
)
.
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