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Mathematics
Mathematics
Problem
The value of
f
(
0
)
f(0)
f
(
0
)
so that
f
(
x
)
=
−
e
x
+
2
x
x
f(x) = \frac{-e^x + 2^x}{x}
f
(
x
)
=
x
−
e
x
+
2
x
may be continuous at
x
=
0
x = 0
x
=
0
is - (A)
−
ln
2
-\ln 2
−
ln
2
(B) 0 (C) 4 (D)
ln
(
2
e
)
\ln\left(\frac{2}{e}\right)
ln
(
e
2
)
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