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Problem
Problem
Statement I
In any triangle ABC, the square of the length of the bisector AD is
b
c
{
1
−
a
2
(
b
+
c
)
2
}
bc\left\{1 - \frac{a^2}{(b+c)^2}\right\}
b
c
{
1
−
(
b
+
c
)
2
a
2
}
.
Statement II
In any triangle ABC length of bisector AD is
2
b
c
(
b
+
c
)
cos
(
A
2
)
\frac{2bc}{(b+c)} \cos\left(\frac{A}{2}\right)
(
b
+
c
)
2
b
c
cos
(
2
A
)
.
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