Problem

Problem

Match the statement of Column I with values of Column II
Column-IColumn-II
(A) If α,β,γ\alpha, \beta, \gamma and δ\delta are four solutions of the equation tan⁡(θ+π4)=3tan⁡3θ\tan\left(\theta + \frac{\pi}{4}\right) = 3 \tan 3\theta , no two of which have equal tangents, then the value of tan⁡α+tan⁡β+tan⁡γ+tan⁡δ\tan \alpha + \tan \beta + \tan \gamma + \tan \delta is(p) 2\sqrt{2}
(B) If cos⁡(θ1−θ2)cos⁡(θ1+θ2)+cos⁡(θ3+θ4)cos⁡(θ3−θ4)=0\frac{\cos(\theta_1 - \theta_2)}{\cos(\theta_1 + \theta_2)} + \frac{\cos(\theta_3 + \theta_4)}{\cos(\theta_3 - \theta_4)} = 0 then tan⁡θ1tan⁡θ2tan⁡θ3tan⁡θ4=\tan \theta_1 \tan \theta_2 \tan \theta_3 \tan \theta_4 =(q) 3\sqrt{3}
(C) If sec⁡(α−β),sec⁡α\sec(\alpha - \beta), \sec \alpha and sec⁡(α+β)\sec(\alpha + \beta) are in A.P. (with β≠0\beta \ne 0 ), then cos⁡αsec⁡β2=\cos \alpha \sec \frac{\beta}{2} =(r) -1
(D) If cos⁡α=2cos⁡β−12−cos⁡β\cos \alpha = \frac{2 \cos \beta - 1}{2 - \cos \beta} ( 0<α<β<π0 < \alpha < \beta < \pi ), then tan⁡α2tan⁡β2\frac{\tan \frac{\alpha}{2}}{\tan \frac{\beta}{2}} is equal to(s) 0

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