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Mathematics
Problem
Let
y
=
y
(
x
)
y = y(x)
y
=
y
(
x
)
be the solution curve of the differential equation,
(
y
2
−
x
)
d
y
d
x
=
1
(y^2 - x)\frac{dy}{dx} = 1
(
y
2
−
x
)
d
x
d
y
=
1
, satisfying
y
(
0
)
=
1
y(0) = 1
y
(
0
)
=
1
. This curve intersects the x-axis at a point whose abscissa is: [JEE-MAIN ONLINE-2020] (1)
2
+
e
2 + e
2
+
e
(2)
2
2
2
(3)
2
−
e
2 - e
2
−
e
(4)
−
e
-e
−
e
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