Mathematics

Mathematics

Problem

If ∫dx1+sin⁡x=tan⁡(x2+a)+b\int \frac{dx}{1 + \sin x} = \tan\left(\frac{x}{2} + a\right) + b, then (a) a=π4, b=3a = \frac{\pi}{4},\, b = 3 (b) a=−π4, b=3a = -\frac{\pi}{4},\, b = 3 (c) a=π4, b=arbitrary constanta = \frac{\pi}{4},\, b = \text{arbitrary constant} (d) a=−π4, b=arbitrary constanta = -\frac{\pi}{4},\, b = \text{arbitrary constant} (a) a=π4, b=3a = \frac{\pi}{4},\, b = 3 (b) a=−π4, b=3a = -\frac{\pi}{4},\, b = 3 (c) a=π4, b=arbitrary constanta = \frac{\pi}{4},\, b = \text{arbitrary constant} (d) a=−π4, b=arbitrary constanta = -\frac{\pi}{4},\, b = \text{arbitrary constant}

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