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Mathematics
Problem
If the lines
3
x
−
4
y
+
4
=
0
3x - 4y + 4 = 0
3
x
−
4
y
+
4
=
0
and
6
x
−
8
y
−
7
=
0
6x - 8y - 7 = 0
6
x
−
8
y
−
7
=
0
are tangents to a circle, then the diameter of the circle is a.
3
2
\frac{3}{2}
2
3
b. 3 c.
5
2
\frac{5}{2}
2
5
d. 5
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