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Mathematics
Problem
Let A be the centre of the circle
x
2
+
y
2
−
2
x
−
4
y
−
20
=
0
x^2 + y^2 - 2x - 4y - 20 = 0
x
2
+
y
2
−
2
x
−
4
y
−
20
=
0
and B(1, 7) and D(4, -2) are points on the circle then, if tangents be drawn at B and D, which meet at C, then area of quadrilateral ABCD is - (A) 150 (B) 75 (C)
75
2
\frac{75}{2}
2
75
(D) None of these
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