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Mathematics
Mathematics
Problem
If one of the diameters of the circle, given by the equation,
x
2
+
y
2
−
4
x
+
6
y
−
12
=
0
x^2 + y^2 - 4x + 6y - 12 = 0
x
2
+
y
2
−
4
x
+
6
y
−
12
=
0
, is a chord of a circle
S
S
S
, whose centre is at
(
−
3
,
2
)
(-3, 2)
(
−
3
,
2
)
, then the radius of
S
S
S
is : [JEE(Main)-2016] (1)
5
2
5\sqrt{2}
5
2
(2)
5
3
5\sqrt{3}
5
3
(3) 5 (4) 10
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