Problem

Problem

If area of

\triangle ABC

,

\Delta

and

\angle C

, are given and if the side

c

opposite to given angles is minimum, then a.

a = \sqrt{\frac{2\Delta}{\sin C}}

b.

b = \sqrt{\frac{2\Delta}{\sin C}}

c.

a = \frac{4\Delta}{\sin C}

d.

b = \frac{4\Delta}{\sin^2 C}

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