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Mathematics
Problem
If
4
x
+
7
x
(
x
+
1
)
(
x
+
3
)
=
A
x
+
B
x
+
1
+
C
x
+
3
\displaystyle \frac{4x+7}{x(x+1)(x+3)}=\frac{A}{x}+\frac{B}{x+1}+\frac{C}{x+3}
x
(
x
+
1
)
(
x
+
3
)
4
x
+
7
=
x
A
+
x
+
1
B
+
x
+
3
C
, then
B
B
B
equals a)
3
2
\dfrac{3}{2}
2
3
b)
−
3
2
-\dfrac{3}{2}
−
2
3
c)
−
5
2
-\dfrac{5}{2}
−
2
5
d) \dfrac{11}{4}
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