Ethanoic acid is neutralized by sodium hydroxide.
CH3COOH(aq)+NaOH(aq)→CH3COONa(aq)+H2O(l)
When 0.048 moles of ethanoic acid is mixed with 0.040 moles of sodium hydroxide, the heat energy change of the reaction, Q , is 2.09 kJ. Calculate the enthalpy change, ΔH⊖ , of the reaction.