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Mathematics
Problem
Let
f
:
R
∖
{
2
}
→
R
∖
{
0
}
f:\mathbb{R}\setminus\{2\}\to\mathbb{R}\setminus\{0\}
f
:
R
∖
{
2
}
→
R
∖
{
0
}
be given by
f
(
x
)
=
1
x
−
2
f(x)=\dfrac{1}{x-2}
f
(
x
)
=
x
−
2
1
. The inverse
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
is a)
f
−
1
(
x
)
=
1
x
−
2
f^{-1}(x)=\dfrac{1}{x-2}
f
−
1
(
x
)
=
x
−
2
1
b)
f
−
1
(
x
)
=
1
x
f^{-1}(x)=\dfrac{1}{x}
f
−
1
(
x
)
=
x
1
c)
f
−
1
(
x
)
=
1
x
+
2
f^{-1}(x)=\dfrac{1}{x}+2
f
−
1
(
x
)
=
x
1
+
2
d)
f
−
1
(
x
)
=
2
−
1
x
f^{-1}(x)=2-\dfrac{1}{x}
f
−
1
(
x
)
=
2
−
x
1
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