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Problems
Let
f
(
x
)
=
{
sin
x
,
for
x
≥
0
1
−
cos
x
,
for
x
≤
0
and
g
(
x
)
=
e
x
.
f(x) = \begin{cases} \sin x, & \text{for } x \geq 0 \\ 1 - \cos x, & \text{for } x \leq 0 \end{cases} \text{ and } g(x) = e^x.
f
(
x
)
=
{
sin
x
,
1
−
cos
x
,
for
x
≥
0
for
x
≤
0
and
g
(
x
)
=
e
x
.
…
Mathematics
Problem
Let
f
(
x
)
=
{
sin
x
,
for
x
≥
0
1
−
cos
x
,
for
x
≤
0
and
g
(
x
)
=
e
x
.
f(x) = \begin{cases} \sin x, & \text{for } x \geq 0 \\ 1 - \cos x, & \text{for } x \leq 0 \end{cases} \text{ and } g(x) = e^x.
f
(
x
)
=
{
sin
x
,
1
−
cos
x
,
for
x
≥
0
for
x
≤
0
and
g
(
x
)
=
e
x
.
Then LHD of
(
g
∘
f
)
(g \circ f)
(
g
∘
f
)
at
x
=
0
x = 0
x
=
0
is (a) 1 (b) -1 (c) 0 (d) None of these
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