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Problems
Define
p
(
x
)
=
{
∣
x
−
1
∣
x
−
1
,
x
≠
1
,
0
,
x
=
1.
p(x)= \begin{cases} \dfrac{|x-1|}{\,x-1\,}, & x\ne 1,\\ 0, & x=1. \end{cases}
p
(
x
)
=
⎩
⎨
⎧
x
−
1
∣
x
−
1∣
,
0
,
x
=
1
,
x
=
1.
…
Mathematics
Problem
Define
p
(
x
)
=
{
∣
x
−
1
∣
x
−
1
,
x
≠
1
,
0
,
x
=
1.
p(x)= \begin{cases} \dfrac{|x-1|}{\,x-1\,}, & x\ne 1,\\ 0, & x=1. \end{cases}
p
(
x
)
=
⎩
⎨
⎧
x
−
1
∣
x
−
1∣
,
0
,
x
=
1
,
x
=
1.
What is the magnitude of the jump discontinuity of
p
p
p
at
x
=
1
x=1
x
=
1
? a)
−
2
-2
−
2
b)
1
1
1
c)
2
2
2
d)
0
0
0
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