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Mathematics
Mathematics
Problem
A function
g
g
g
is defined by
g
(
x
)
=
{
x
2
−
9
x
−
3
,
x
≠
3
b
,
x
=
3
g(x)=\begin{cases} \dfrac{x^{2}-9}{x-3}, & x\neq 3\\ b, & x=3 \end{cases}
g
(
x
)
=
⎩
⎨
⎧
x
−
3
x
2
−
9
,
b
,
x
=
3
x
=
3
For which value of
b
b
b
is
g
g
g
continuous at
x
=
3
x=3
x
=
3
? a)
0
0
0
b)
6
6
6
c)
3
3
3
d)
−
6
-6
−
6
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