Rutherford scattering. A particle of charge q1 and mass m scatters off a fixed Coulomb center of charge q2. The potential energy is U(r)=rq1q2 (in Gaussian units). Show that the differential cross section is given by the Rutherford formula:
dΩdσ=(4Eq1q2)2sin4(θ/2)1
where E=21mv2 is the kinetic energy of the incoming particle.