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Problem
Problem
Calculate angular width of central maxima if
λ
=
6000
A
˚
\lambda = 6000 \text{ \AA}
λ
=
6000
A
˚
,
a
=
18
×
10
−
5
cm
a = 18 \times 10^{-5} \text{ cm}
a
=
18
×
1
0
−
5
cm
: (a)
20
∘
20^\circ
2
0
∘
(b)
40
∘
40^\circ
4
0
∘
(c)
30
∘
30^\circ
3
0
∘
(d)
260
∘
260^\circ
26
0
∘
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