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Mathematics
Problem
If
y
=
1
+
x
2
+
x
4
1
+
x
+
x
2
y = \frac{1+x^2+x^4}{1+x+x^2}
y
=
1
+
x
+
x
2
1
+
x
2
+
x
4
and
d
y
d
x
=
a
x
+
b
\frac{dy}{dx} = ax + b
d
x
d
y
=
a
x
+
b
, then values of a & b are - (A)
a
=
2
,
b
=
1
a = 2, b = 1
a
=
2
,
b
=
1
(B)
a
=
−
2
,
b
=
1
a = -2, b = 1
a
=
−
2
,
b
=
1
(C)
a
=
2
,
b
=
−
1
a = 2, b = -1
a
=
2
,
b
=
−
1
(D)
a
=
−
2
,
b
=
−
1
a = -2, b = -1
a
=
−
2
,
b
=
−
1
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