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Mathematics
Mathematics
Problem
If
y
=
1
4
u
4
y = \frac{1}{4}u^4
y
=
4
1
u
4
,
u
=
2
3
x
3
+
5
u = \frac{2}{3}x^3 + 5
u
=
3
2
x
3
+
5
, then
d
y
d
x
=
\frac{dy}{dx} =
d
x
d
y
=
(a)
1
27
x
2
(
2
x
3
+
15
)
3
\frac{1}{27}x^2(2x^3+15)^3
27
1
x
2
(
2
x
3
+
15
)
3
(b)
2
27
x
(
2
x
3
+
5
)
3
\frac{2}{27}x(2x^3+5)^3
27
2
x
(
2
x
3
+
5
)
3
(c)
2
27
x
2
(
2
x
3
+
15
)
3
\frac{2}{27}x^2(2x^3+15)^3
27
2
x
2
(
2
x
3
+
15
)
3
(d) None of these
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