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Mathematics
Mathematics
Problem
The area of the closed figure bounded by
y
=
x
y = x
y
=
x
,
y
=
−
x
y = -x
y
=
−
x
& the tangent to the curve
y
=
x
2
−
5
y = \sqrt{x^2 - 5}
y
=
x
2
−
5
at the point
(
3
,
2
)
(3, 2)
(
3
,
2
)
is - (A) 5 (B)
2
5
2\sqrt{5}
2
5
(C) 10 (D)
5
2
\frac{5}{2}
2
5
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