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Mathematics
Mathematics
Problem
If
2
x
=
y
1
5
+
y
−
1
5
2x = y^{\frac{1}{5}} + y^{-\frac{1}{5}}
2
x
=
y
5
1
+
y
−
5
1
and
(
x
2
−
1
)
d
2
y
d
x
2
+
λ
x
d
y
d
x
+
k
y
=
0
(x^2 - 1)\frac{d^2y}{dx^2} + \lambda x \frac{dy}{dx} + ky = 0
(
x
2
−
1
)
d
x
2
d
2
y
+
λ
x
d
x
d
y
+
k
y
=
0
, then
λ
+
k
\lambda + k
λ
+
k
is equal to:
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