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Problem
Problem
Solve the system of equations
2
x
+
y
=
256
2^{\sqrt{x} + \sqrt{y}} = 256
2
x
+
y
=
256
and
log
10
x
y
−
log
10
(
3
2
)
=
1.
\log_{10} \sqrt{xy} - \log_{10} \left( \frac{3}{2} \right) = 1.
lo
g
10
x
y
−
lo
g
10
(
2
3
)
=
1.
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