For the function
h(x)=x2+32x2+1,
determine a concrete numerical bound for x that guarantees the function value is within 0.001 of its limiting value at infinity.
a. (i) Find the smallest real number M (to the nearest integer) such that
x2+32x2+1−2<0.001
whenever x>M. Show all steps leading to your answer.
b. (ii) Verify explicitly that the inequality in part (i) indeed holds for x=M.