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Physics
Physics
Problem
The potential energy of a particle of mass
m
m
m
is given by
V
(
x
)
=
{
E
0
;
0
≤
x
≤
1
0
;
x
>
1
V(x) = \begin{cases} E_0; & 0 \le x \le 1 \\ 0; & x > 1 \end{cases}
V
(
x
)
=
{
E
0
;
0
;
0
≤
x
≤
1
x
>
1
λ
1
\lambda_1
λ
1
and
λ
2
\lambda_2
λ
2
are the de-Broglie wavelengths of the particle, when
0
≤
x
≤
1
0 \le x \le 1
0
≤
x
≤
1
and
x
>
1
x > 1
x
>
1
respectively. If the total energy of particle is
2
E
0
2E_0
2
E
0
, find
λ
1
/
λ
2
\lambda_1 / \lambda_2
λ
1
/
λ
2
.
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