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Mathematics
Mathematics
Problem
If range of the function
f
(
x
)
=
tan
−
1
(
3
x
2
+
b
x
+
3
)
f(x) = \tan^{-1}(3x^2 + bx + 3)
f
(
x
)
=
tan
−
1
(
3
x
2
+
b
x
+
3
)
,
x
∈
R
x \in R
x
∈
R
is
[
0
,
π
2
]
\left[0, \frac{\pi}{2}\right]
[
0
,
2
π
]
, then square of sum of all possible values of
b
b
b
will be a. 0 b. 18 c. 72 d. None of these
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