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Physics
Physics
Problem
Calculate the approximate altitude (above Earth’s surface) of a geostationary satellite. Take
G
=
6.67
×
10
−
11
N m
2
kg
−
2
G = 6.67\times10^{-11}\,\text{N m}^2\text{kg}^{-2}
G
=
6.67
×
1
0
−
11
N m
2
kg
−
2
,
M
⊕
=
5.97
×
10
24
kg
M_{\oplus}=5.97\times10^{24}\,\text{kg}
M
⊕
=
5.97
×
1
0
24
kg
,
R
⊕
=
6.37
×
10
6
m
R_{\oplus}=6.37\times10^{6}\,\text{m}
R
⊕
=
6.37
×
1
0
6
m
and orbital period
T
=
24
h
T = 24\,\text{h}
T
=
24
h
. a)
2.3
×
10
7
m
2.3\times10^{7}\,\text{m}
2.3
×
1
0
7
m
b)
4.2
×
10
7
m
4.2\times10^{7}\,\text{m}
4.2
×
1
0
7
m
c)
3.6
×
10
7
m
3.6\times10^{7}\,\text{m}
3.6
×
1
0
7
m
d)
1.5
×
10
7
m
1.5\times10^{7}\,\text{m}
1.5
×
1
0
7
m
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