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Mathematics
Problem
Find the particular solution of the differential equation
(
x
+
1
)
d
y
d
x
=
2
e
−
y
−
1
,
it being given that
y
=
0
when
x
=
0.
[CBSE 2012]
(x+1) \frac{dy}{dx} = 2e^{-y} - 1, \text{ it being given that } y = 0 \text{ when } x = 0. \text{ [CBSE 2012]}
(
x
+
1
)
d
x
d
y
=
2
e
−
y
−
1
,
it being given that
y
=
0
when
x
=
0.
[CBSE 2012]
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