Problem

Problem

Position vector (with respect to centre) velocity vector and acceleration vector of a particle in circular motion are r=(3i^−4j^)\mathbf{r} = (3\hat{i} - 4\hat{j}) m, v=(4i^−aj^)\mathbf{v} = (4\hat{i} - a\hat{j}) ms-1 and a=(−6i^+bj^)\mathbf{a} = (-6\hat{i} + b\hat{j}) ms-2. Speed of particle is constant. Match the following two columns.
Column IColumn II (SI units)
(a) Value of aa(p) 8
(b) Value of bb(q) 3
(c) Radius of circle(r) 5
(d) r⋅(v×a)\mathbf{r} \cdot (\mathbf{v} \times \mathbf{a})(s) None

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