Chemistry

Chemistry

Problem

For the given cell PtD2/D+∣∣H+∣PtH2\text{Pt}_{D_2/D^+} || \text{H}^+ | \text{Pt}_{H_2} if ED2/D+∘=0.003 VE_{D_2/D^+}^\circ = 0.003 \text{ V} , what will be ratio of D+D^+ and H+\text{H}^+ at 25∘C25^\circ \text{C} when the reaction : D2+2H+→2D++H2D_2 + 2\text{H}^+ \rightarrow 2D^+ + \text{H}_2 attains equilibrium : a. 1.341.34 b. 1.241.24 c. 1.1241.124 d. 1.451.45

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