Physics

Physics

Problem

In a series RLC circuit with R=20 ΩR = 20\,\Omega, L=50 mHL = 50\,\text{mH} and C=200 μFC = 200\,\mu\text{F}, the source voltage amplitude is 10 V10\,\text{V}. If the driving frequency is doubled from its resonant value, what is the ratio of the new current amplitude to that at resonance? a) 0.510.51 b) 0.840.84 c) 0.640.64 d) 0.410.41

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