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Problems
Mathematics
Mathematics
Problem
In degrees, solve
tan
(
2
θ
−
30
∘
)
=
tan
45
∘
\tan\left(2\theta - 30^\circ\right) = \tan 45^\circ
tan
(
2
θ
−
3
0
∘
)
=
tan
4
5
∘
for
0
∘
≤
θ
<
180
∘
0^\circ \le \theta < 180^\circ
0
∘
≤
θ
<
18
0
∘
. a)
θ
=
37.5
∘
,
82.5
∘
,
127.5
∘
,
172.5
∘
\theta = 37.5^\circ,\;82.5^\circ,\;127.5^\circ,\;172.5^\circ
θ
=
37.
5
∘
,
82.
5
∘
,
127.
5
∘
,
172.
5
∘
b)
θ
=
37.5
∘
\theta = 37.5^\circ
θ
=
37.
5
∘
c)
θ
=
37.5
∘
,
127.5
∘
\theta = 37.5^\circ,\;127.5^\circ
θ
=
37.
5
∘
,
127.
5
∘
d)
θ
=
60
∘
,
150
∘
\theta = 60^\circ,\;150^\circ
θ
=
6
0
∘
,
15
0
∘
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